(1-2i)z^2+6iz-12i=0

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Solution for (1-2i)z^2+6iz-12i=0 equation: 


Simplifying
(1 + -2i) * z2 + 6iz + -12i = 0

Reorder the terms for easier multiplication:
z2(1 + -2i) + 6iz + -12i = 0
(1 * z2 + -2i * z2) + 6iz + -12i = 0

Reorder the terms:
(-2iz2 + 1z2) + 6iz + -12i = 0
(-2iz2 + 1z2) + 6iz + -12i = 0

Reorder the terms:
-12i + 6iz + -2iz2 + 1z2 = 0

Solving
-12i + 6iz + -2iz2 + 1z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1z2' to each side of the equation.
-12i + 6iz + -2iz2 + 1z2 + -1z2 = 0 + -1z2

Combine like terms: 1z2 + -1z2 = 0
-12i + 6iz + -2iz2 + 0 = 0 + -1z2
-12i + 6iz + -2iz2 = 0 + -1z2
Remove the zero:
-12i + 6iz + -2iz2 = -1z2

Combine like terms: -1z2 + z2 = 0
-12i + 6iz + -2iz2 + z2 = 0

The solution to this equation could not be determined.

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